Orthographic LODs – Part I

NOTE: I’m going to try something new here: rather than write about something I have already solved, this series will be my notes as I work through this problem. As such, this is *not* a guide. The code is a pile of hacks and I will make silly mistakes.

The Problem:

I am working on a city-building game. I want to be able to use detailed models with large numbers of polygons and textures, but without the runtime rendering cost that entails. To do so, I want to pre-render detailed models as textures for lower level-of-detail (LOD) models. This is not a particularly original solution (it is the system SimCity 4 uses). There are a few restrictions implied by this choice:

  • Camera projection must be orthographic.
    • A perspective projection will appear to skew the model the further it gets from the center of the view. Orthographic projection will not.
  • Camera angle must be fixed (or a finite set of fixed positions).
    • While camera *position* is irrelevant (because an orthographic projection doesn’t affect depth), its rotation is not. Each camera angle needs its own LOD image. Therefore, we need a small number of them.

The process is simple enough: render the detail model for each view. Projecting the vertices of the LOD model with the same view produces the proper texture coordinates for the LOD. Then, pack all of the rendered textures into an atlas.

Orthographic Rendering

Rendering an orthographic projection is, conceptually, very straightforward. After transforming the world to camera space (moving the camera to the origin, and aligning the z-axis with the camera’s forward view), we select a box of space and map it onto a unit cube (that is, a cube with a minimum point of (-1, -1, -1) and a maximum point of (1, 1, 1).) The z-component of each point is then discarded.

I will not get into the math here. Wikipedia has a nicely concise explanation.

What this *means* is that we can fit this box tightly to the model we want to render. With clever application of glViewport, we could even render all of our views in one go. (At the moment, I have not yet implemented this.) This makes building the texture atlas much simpler.

Calculating Camera-space LOD

To get this tight fit, we need to know the bounds of the rendered model in camera space. Since we are projecting onto the LOD model, *its* bounds are what we’re concerned with. (This implies, by the way, that the LOD model must completely enclose the detail model.)

struct AABB {
    vec3 min;
    vec3 max;
};

AABB
GetCameraSpaceBounds(Model * model, mat4x4 camera_from_model) {
    AABB result;

    vec4 * model_verts = model->vertices;
    vec4 camera_vert = camera_from_model * model_verts[0];

    // We don't initialize to 0 vectors, because we don't
    // guarentee the model is centered on the origin.
    result.min = vec3(camera_vert);
    result.max = vec3(camera_vert);

    for (u32 i = 1; i < model->vertex_count; ++i) {
        camera_vert = camera_from_model * model_verts[i];

        result.min.x = min(result.min.x, camera_vert.x);
        result.min.y = min(result.min.y, camera_vert.y);
        result.min.z = min(result.min.z, camera_vert.z);

        result.max.x = max(result.max.x, camera_vert.x);
        result.max.y = max(result.max.y, camera_vert.y);
        result.max.z = max(result.max.z, camera_vert.z);
    }

    return result;
}

This bounding box gives us the clip volume to render.

AABB lod_bounds = GetCameraSpaceBounds(lod_model, camera_from_model);

mat4x4 eye_from_camera = OrthoProjectionMatrix(
    lod_bounds.max.x, lod_bounds.min.x,  // right, left
    lod_bounds.max.y, lod_bounds.min.y,  // top, bottom
    lod_bounds.min.z, lod_bounds.max.z); // near, far

mat4x4 eye_from_model = eye_from_camera * camera_from_model;

Rendering LOD Texture

Rendering to a texture requires a framebuffer. (In theory, we could also simply render to the screen and extract the result with glGetPixels. However, that limits us to a single a single color output and makes it more difficult to do any GPU postprocessing.)

After binding a new framebuffer, we need to create the texture to render onto:

glGenTextures(1, &result->texture);
glActiveTexture(GL_TEXTURE0);
glBindTexture(GL_TEXTURE_2D, result->texture);

// render_width and render_height are the width and height of the 
// camera space lod bounding box.
glTexImage2D(
    GL_TEXTURE_2D, 0, GL_RGBA, render_width, render_height, 0, GL_RGBA, GL_UNSIGNED_BYTE, 0
);

glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MAX_LEVEL, 0);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_WRAP_S, GL_CLAMP_TO_EDGE);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_WRAP_T, GL_CLAMP_TO_EDGE);

glFramebufferTexture(GL_FRAMEBUFFER, GL_COLOR_ATTACHMENT0, result->texture, 0);

glViewport(0, 0, render_width, render_height);

This gives us a texture large enough to fit our rendered image, attaches it to the framebuffer, and sets the viewport to the entire framebuffer. To render multiple views to one texture, we’d allocate a larger texture, and use the viewport call to selected the target region.

Now we simply render the detail model with the eye_from_model transform calculated earlier. The result:

lod_test_02
(The detail shader used simply maps position to color.)

That’s all for now. Next time: how do we light this model?

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How bad is rand() % range?

“Pick a random number between 0 and 10.”

It’s a fairly basic task, often used as a project in introductory programming classes and extended language examples. The most common and straightforward solution is modulus. (Indeed, most CS classes use this exercise purely to introduce the concept of modulus.)

int number = rand() % range;

However, there is a problem with this method — it skews the distribution of numbers produced.

C’s rand() returns an integer in the range [0, RAND_MAX].
For illustration, let’s:
Assume RAND_MAX = 8
Assume rand is a perfect random distribution. (Equal chance of returning any integer in range.)

Let range = 5.
The possible values for number are then:

[0 % 5,
 1 % 5,
 2 % 5,
 3 % 5,
 4 % 5,
 5 % 5,
 6 % 5,
 7 % 5,
 8 % 5]
 =>
 [0, 1, 2, 3, 4, 0, 1, 2, 3]

You’ll notice that the [0, 3] range appears *twice*, but 4 only once. Therefore, there is only a 1/9 chance that rand() % 5 will generate a 4, but all other values have a probability of 2/9. That said, there *are* combinations of RAND_MAX and range that will work: for example, RAND_MAX = 7, range = 4:

[0, 1, 2, 3, 4, 5, 6, 7] % 4 => [0, 1, 2, 3, 0, 1, 2, 3]

Of course, on a real system, RAND_MAX is never so low. To analyse the actual ranges, we’ll need to rely on more advanced statistics.

The Goodness of Fit (GOF) test is a method of testing whether the distribution of a given sample agrees with the theoretical distribution of the entire population. This test relies on the \chi^2 test statistic (read ‘chi-squared’). We derive our \chi^2 by:

\chi^2=\sum\frac{(expected - observed)^2}{expected}

That is to say, we take a sample of data — in our case, iterations of rand(). This data is (must be) categorical, separable into discrete ‘buckets’ of values. In this case, the buckets are the integer values mod range. We then compare the expected and observed counts in each bucket, and sum the result for all buckets. (Important caveat: for this to provide a valid result, the expected count *must* be at least 5 for all buckets.)

With \chi^2 in hand, we can calculate the p-value of our data. The p-value is the probability that the theoretical distribution is correct, based on our sample. To calculate the p-value, we use the \chi^2cdf function. The cdf, or Cumulative Distribution Function, is the area underneath the distribution function for a given distribution. The value we are interested in is the area to the right of our \chi^2 statistic, so our calculation looks like:

1-\chi^2cdf(\chi^2, df)

Because this is a probability distribution, the total area under the curve is 1. Subtracting the area up to our \chi^2, we’re left with the right tail, which is our p-value. The higher our p-value, the closer we are to the theoretical distribution.

You’ll note one other variable in that equation: df. This is the ‘degree of freedom’ in the distribution. The \chi^2 distribution function changes with sample size — the degree of freedom is how this is represented. For a Goodness of Fit test, the degree of freedom is equal to the number of buckets, minus one.

Now for the actual test.

Since we expect rand() to approximate a perfect random distribution (it doesn’t, on most systems, but that is a separate issue), our theoretical, expected count in each bucket is equal to the number of trials divided by the number of buckets (our range.) For the Goodness of Fit test, we need a minimum of five expected counts in each bucket. Therefore, to test a given range we need to generate at least range*5 trials.

I wrote a short program in C++ to calculate \chi^2 for all ranges of rand(). Note that this does not directly tell us our p-values. Instead, it generates a Scilab script to calculate and plot them. (Actually evaluating \chi^2cdf requires Calculus beyond what I’m familiar with.)

The resulting plot is interesting:
df_vs_pval_randmod

Below ~4000, many ranges produce a reasonable distribution. However, above that point, the vast majority of ranges lead to *highly* skewed distributions (p = 0).

So, what’s the takeaway? How bad *is* rand() % range?

Pretty bad! The more important question, however, is whether you care.

Cryptography has very strict standards on the distribution of its random numbers. Not only do you not want to use modulus to remap ranges in crypto, you don’t want to be using rand() in the first place! Other applications are far less demanding. The slight skew is likely irrevelant in a game, for example. (Doom rather famously uses a single static table for its random number generator, foregoing rand() altogether.)

Finally: This post is *almost certainly* littered with errors. Most glaringly, assuming rand() to have a proper random distribution is incorrect. This is intended more as an exploration of the concept than a rigorous proof. However, corrections are welcome!

Z-Ordering for Isometric Tile Maps

For a 2D, top-down view, the natural ordering of a tile map is a linear array, organized as a 2D matrix. The coordinates of any given tile can be calculated by `y * width + x` (row-major) or `x * height + y` (column-major). Conversely, you can calculate the x and y from the index of a given tile. [1] This is not the only way to represent such a map — for example, if you have an extremely large map it may be worthwhile to ‘swizzle’ the array, storing blocks of tiles sequentially rather than entire rows. [2]

The advantage of the top-down view is that order of rendering is less important. Tiles do not overlap, so the order they are rendered to the screen does not affect the final image. Therefore, rearranging the tile array has no visible effect on rendering. The matrix view of the map is easy to reason about, so this is convenient.

An isometric view, on the other hand, is a different matter.
Continue reading

FTJ2014 Post-mortem Part II – Animation

Unlike rendering, I went into this jam with no clue how to do animation. Fortunately, it turns out to be fairly simple (in part thanks to my per-entity rendering setup.)

First, a brief bit of background, for anyone unfamiliar with rendering:

Each vertex drawn has three properties: position, color, and texture coordinates. The rest of the pixels draw are determined by linear interpolation between connected vertices. Which vertices are connected depends on the primitive type defined when we send the vertex buffer to the GPU. In Majo, everything is rendered as Quads (4 consecutive vertices create a single face.) Finally, by convention, the elements of the position vector are referred to by the familiar (x, y, z), but texture coordinates are labeled (u, v, w).

So, the following code renders a 16×16 square starting at the origin (top-left of screen), textured with a 32×32 block of the current texture, starting at the top-left of the texture image:

void Foo::render(sf::Vertex * quad) const
{
    quad[0].position = sf::Vector2f(0, 0);
    quad[1].position = sf::Vector2f(16, 0);
    quad[2].position = sf::Vector2f(16, 16);
    quad[3].position = sf::Vector2f(0, 16);

    quad[0].texCoords = sf::Vector2f(0, 0);
    quad[1].texCoords = sf::Vector2f(32, 0);
    quad[2].texCoords = sf::Vector2f(32, 32);
    quad[3].texCoords = sf::Vector2f(0, 32);
}

(There’s no requirement for texture size and actual rendered size to be related, but direct multiples prevent squashing and stretching.)

What this means is we can place multiple sprites on a single texture image (a spritesheet), and slice out the portion we want to render. Which means that *animating* these sprites is just a matter of changing which slice of the spritesheet we render.

A single frame of animation, then, is simply a rectangle indicating what part of the spritesheet to render:

struct AnimationFrame
{
    sf::Vector2f uv;  // Offset into the texture.
    sf::Vector2f spriteSize;  // Size of the sprite on the texture.
};

And an animation consists of a list of frames, with some bookkeeping regarding when to switch:

class Animation
{
private:
    /* Container for a list of animation frames. */
    std::vector<const AnimationFrame> m_frames;
    int m_currentFrame;

    int m_ticksPerFrame;
    int m_ticksSinceLastFrame;

public:
    // Constructors / Accessors elided.

    /* Start the animation. */
    void start();
    /* Update call.  Advances the animation. */
    void update();
    /* 
     * Render the texture coords to quad.
     * Does not touch position -- that is to be set by the entity.
     */
    void render(sf::Vertex * quad) const;
};

The render method allows the owning entity to pass a quad to render the appropriate uv coordinates (while still rendering position and color itself.)

We’re not done yet!

The problem is that this class is hefty: a four-frame animation weighs in at 76 bytes, plus overhead incurred by the vector class. Copying this class as a member of every Entity that uses an animation adds up to a lot of memory moving around. (The issue is less the memory usage, and more that allocating, copying, and deallocating that memory is not free.)

The obvious solution is to cache the Animation, and let each entity store a pointer to it. However, we now have a different problem: the timing information and current frame are shared between all entities using a given animation. (Since each entity calls Animation::update, this leads to undesired behavior.)

This leads to the core lesson I learned during this jam: data and state are different things. Separate them.

Our animation frames are data: we load them into memory once, and only read from them. On the other hand, the timing information is *state*, modified on each update. These are two separate concepts, so let’s carve out the stateful bits into their own structure:

struct AnimationState
{
    int frameCount;
    int currentFrame;
    int ticksPerFrame;
    int ticksSinceLast;

    // Methods elided
};

With a bit of trivial setup, each animated Entity now owns an AnimationState, as well as a pointer to an Animation (20 + 4 bytes per Entity on x86). Now we can cache and share Animations all we want, as they are constant data. Animation::render has its signature changed to accept an AnimationState passed in: void render(sf::Vertex * quad, const AnimationState& state) const;

Over 1000 entities, this system saves ~54.6kB of memory. That’s not a lot. However, by enabling caching of Animations, we reduce the amount of initialization code involved, as well as the number of runtime copies/moves neccessary. Decreased memory usage is just a nice bonus.

Next time: design, scope, and some miscellaneous issues encountered over the week.

FTJ2014 Post-mortem I – Rendering

Fuck This Jam 2014 has wrapped up, so I can finally take the time to pop stack and talk about what I’ve learned in the process. Together with a former classmate, I built “Majo no Mahouki” [link], a side-scrolling shoot ’em up. The game itself leaves much to be desired (as to be expected from a 7-day jam), but I think some of the underlying framework code is worth discussing.

The game is built in C++ on top of the SFML library. SFML provides (among other things) a 2D graphics abstraction over OpenGL. The core interface to this abstraction is sf::RenderTarget::draw, which accepts a buffer of vertices and a RenderState (pointing to textures, shaders, etc.) Every call to draw results in a GL draw call. As such, these calls are *not* cheap.

However, the overhead is more or less the same between 4 vertices and 4000. Therefore, the solution is obvious: batching!

Majo handles this by creating a single VertexArray in the Level object (which handles the actual rendering for all in-game sprites). Each Entity, then, has a method with the signature virtual void render(sf::Vertex * quad) const. The level hands each entity a pointer to a quad in its vertex array, and the entity renders itself to it.

An example (default static sprite rendering):

void Entity::render(sf::Vertex * quad) const
{
    const double radius = m_collider.getRadius();
    const sf::Vector2f position = m_collider.getPosition();
    const sf::Vector2f halfsize(radius, radius);

    quad[0].position = sf::Vector2f(position.x - halfsize.x, position.y - halfsize.y);
    quad[1].position = sf::Vector2f(position.x + halfsize.x, position.y - halfsize.y);
    quad[2].position = sf::Vector2f(position.x + halfsize.x, position.y + halfsize.y);
    quad[3].position = sf::Vector2f(position.x - halfsize.x, position.y + halfsize.y);

    quad[0].texCoords = sf::Vector2f(m_spriteBounds.left, m_spriteBounds.top);
    quad[1].texCoords = sf::Vector2f(m_spriteBounds.left + m_spriteBounds.width, m_spriteBounds.top);
    quad[2].texCoords = sf::Vector2f(m_spriteBounds.left + m_spriteBounds.width, m_spriteBounds.top + m_spriteBounds.height);
    quad[3].texCoords = sf::Vector2f(m_spriteBounds.left, m_spriteBounds.top + m_spriteBounds.height);
}

This convention has issues, obviously: Level assumes that each entity only renders 4 vertices, and Entity assumes it is passed 4 vertices to render to. In hindsight, passing a reference to the array and an index into it may be a better calling convention.

In any case, we now have our vertices set up. However, this is not enough. While the vertices define position and texture coordinates, they do *not* define what texture is actually used (nor shaders, nor transforms, though Majo uses neither.) For proper batching, we must sort the list of entities by texture before rendering them to the vertex array:

void Level::render()
{
    m_projectileCount = 0;
    m_enemyCount = 0;

    m_verts.clear();
    m_verts.resize(m_entities.size() * 4);

    // Sort by texture type -- we want to batch drawing by texture.
    std::sort(m_entities.begin(), m_entities.end(), 
        [](const Entity * a, const Entity * b) {
        return a->getTextureId() < b->getTextureId();
    });

    // Scan the list, rendering to vertex buffer and 
    // recording counts of each texture type.
    for (int i = 0; i < m_entities.size(); ++i)
    {
        const TextureId texId = m_entities[i]->getTextureId();
        if (texId == TEXTURE_PROJECTILES) m_projectileCount++;
        else if (texId == TEXTURE_ENEMIES) m_enemyCount++;

        m_entities[i]->render(&m_verts[i * 4]);
    }
}

(A TextureId is Majo’s internal handle to a cached texture.)

Now Level has an array of vertices, and offsets within the array for each texture switch. (This particular method of recording the offset will not scale well, but Majo uses a total of 3 textures, so it works here.) The draw call, then, is straightforward:

void Level::draw(sf::RenderTarget& target, sf::RenderStates states) const
{
    if (m_entities.size() == 0) return;

    const sf::Vertex * projectileVerts = &m_verts[0];
    const sf::Vertex * enemyVerts = &m_verts[m_projectileCount * 4];
    const sf::Vertex * playerVerts = &m_verts[(m_projectileCount + m_enemyCount) * 4];

    states.texture = Resources::getTexture(TEXTURE_PROJECTILES);
    target.draw(projectileVerts, m_projectileCount * 4, sf::Quads, states);

    states.texture = Resources::getTexture(TEXTURE_ENEMIES);
    target.draw(enemyVerts, m_enemyCount * 4, sf::Quads, states);

    states.texture = Resources::getTexture(TEXTURE_PLAYER);
    target.draw(playerVerts, 4, sf::Quads, states);

    // Hacky UI drawing elided.
}

Thus, we can draw all Entities with only 3 calls to RenderTarget::draw. This is a fairly extreme example — while individually rendering entities is prohibitively expensive, it’s not necessarily worthwhile to batch *every* draw. However, it can be done.

Next time, we’ll explore how Majo handles sprite animation.

The Tale of trimZeros, or UI: Detail Counts

Continuing in a similar vein to my last post (Dragging Roads), another post on UI code. My CS professor has a few labs that we come back to and build on over the course of the year — one of these is an RPN calculator, which we built last semester (and which has become a coding kata for me in several languages), and which we are now developing GUIs for: first with Swing, and now on Android. (Spoilers: no, nothing in today’s post is actually related to Android UI in particular.)

Although the calculator code itself works on doubles, as you would expect, the UI stores the currently entered number as a String. This seems like a dirty hack (it is), but in order to support floating point entry and a backspace key, it’s the simplest means. The alternative, using exponentiation to place each digit in the right place on a double, has more nasty corner cases than are worth dealing with in the timeframe of a lab exercise. This String-backed UI has some consequences, namely that the user can input values that are either (a) invalid or (b) look wrong. Today’s post examines (b) — more specifically, removing unnecessary leading zeros.

Trimming zeros is easy, right?

private void trimZeros() {
    if (currentEntry.length() < 1) return;
    
    int i;

    for (i = 0; currentEntry.length() > i 
             && currentEntry.charAt(i) == '0'; ++i);

    currentEntry = currentEntry.substring(i);
}

(currentEntry is the String used to store the current entered number.)

This is somewhat more “clever” than it probably should be, but it’s still straightforward code — find the index of the first non-‘0’ character in the currentEntry string, then lop off the zeros all at once with a substring call.

However, it doesn’t quite preform how we want:

|  Input  |  Output  |
+---------+----------+
|  "0123" |   "123"  |
| "0.123" |  ".123"  |
|   "000" |      ""  |
|     "0" |      ""  |

Leading zeros on integers are trimmed properly, but zero values are reduced to empty strings, and decimal values lose the leading zero. With the exception of the empty strings, these are perfectly valid — feed them into #parseDouble and we’ll get the right double out, but we can do better.

private void trimZeros() {
    if (currentEntry.length() < 1) return;
    
    int i;
    int decimalPoint = currentEntry.indexOf('.');

    for (i = 0; currentEntry.length() - 1 > i 
             && currentEntry.charAt(i) == '0'; ++i) {

        if (i + 1 == decimalPoint) break;
    }

    currentEntry = currentEntry.substring(i);
}

Let’s check our table again:

|  Input  |  Output  |
+---------+----------+
|  "0123" |   "123"  |
| "0.123" | "0.123"  |
|   "000" |     "0"  |
|     "0" |     "0"  |

We’ve made two changes here: first, we never try to consume the last character in the string. Therefore, if we have an input of “00”, we only chop off the first ‘0’, leaving “0” — exactly what we want. Second, we look up the location of the decimal point (if there is one), and ensure we stop one character short of it, preserving a leading zero before the decimal point.

(An aside for those not well versed in Java: #indexOf returns -1 for a character not in the string. Because i starts at 0 and is only incremented, we can guarantee that i + 1 != -1 (overflow excepted — it’s not ever a problem here).)

Minor UI polish like this is not particularly difficult — the total diff between these two methods is 3 lines of code. However, issues like this exist in every system and piece of data that comes close to a user. It’s worth investing the time to hunt them down and fix them, though — users may not notice a well-behaved UI, but they will notice an awkward one.

Dragging Roads

I’m currently working on a game prototype (using C++ and SFML) that involves, among other things, dragging roads on a tilemap. I had a very specific behavior in mind for dragging, which took some work to get right. I’m going to document my results here.

# Plumbing

Before we can even start to worry about how the dragging works, we have to implement a dragging action. SFML exposes events for the mouse being clicked, released, and moved — these form the basis of our action.

//... Inside main loop

sf::Event event;
while (window.pollEvent(event))
{
    switch(event.type)
    {
    //... Other event handling
    case sf::Event::MouseButtonPressed:
        // Map global pixel location to a location relative to the window.
        sf::Vector2f clickPos = window.mapPixelToCoords(
            sf::Vector2i(event.mouseButton.x, event.mouseButton.y)
            m_map->getView());

        // Map this relative pixel location to a specfic tile.
        sf::Vector2i tilePos = m_map->mapPixelToTile(clickPos);

        // Tell the current tool where to start a drag.
        m_currentTool->startDrag(tilePos);
        break;
    case sf::Event::MouseButtonReleased:
        // End the active drag.
        m_currentTool->endDrag();
        break;
    case sf::Event::MouseMoved:
        sf::Vector2f mousePos = window.mapPixelToCoords(
            sf::Vector2i(event.mouseMove.x, event.mouseMove.y)
            m_map->getView());

        sf::Vector2i tilePos = m_map->mapPixelToTile(mousePos);

        // Update the current position of the drag.
        m_currentTool->updateDrag(tilePos);
        break;
    }
}

//...

This is all fairly straightforward: map the mouse coordinates to a particular tile and pass off to the Tool class. We now have the groundwork in place:

class Tool
{
private:
    bool isDragging;
    sf::Vector2i m_dragStart;
    sf::Vector2i m_dragCurrent;
    std::vector<sf::Vector2i> m_tiles;

    void updatePath();  // <-- The magic happens here.

public:
    void startDrag(const sf::Vector2i& pos)
    {
        if (m_isDragging) return;

        m_isDragging = true;
        m_tiles.push_back(pos);
        m_dragStart = pos;
        m_dragCurrent = pos;
    }
    void updateDrag(const sf::Vector2i& pos)
    {
        if (!m_isDragging) return;

        m_dragCurrent = pos;
        updatePath();
    }
    void endDrag()
    {
        if (!m_isDragging) return;
        m_tiles.clear();
    }
};

# The Algorithm

Our goal is to produce a list of tile coordinates that connect m_dragStart and m_dragCurrent. We want a linear path, with an optional dogleg, i.e.:

* * * * * *
          * *
            * *
              * *

Finally, if there is a diagonal segment, we want the tip to “rotate” as we extend the drag:

* * *
    * *
      *
    |
    v
* * *
    * *
      * *
    |
    v
* * *
    * *
      * *
        *

The first draft of the algorithm succeeds at everything except rotating:

void Tool::updatePath()
{
    // Clear output vector.
    m_tiles.clear();

    sf::Vector2i curr = m_dragStart;

     while (curr != m_dragCurrent) {
        m_tiles.push_back(curr);

        // Signed deltas
        const int dx = curr.x - m_dragCurr.x;
        const int dy = curr.y - m_dragCurr.y;

        if (abs(dx) > abs(dy)) {
            curr.x -= 1 * sign(dx);
        }
        else {
            curr.y -= 1 * sign(dy);
        }

    }

    m_tiles.push_back(curr);
}

(The sign function simply maps negative numbers to -1, positive numbers to 1, and 0 to 0.)

This is a very simple algorithm, but it doesn’t handle the diagonals exactly the way we’d like. The “rotation” of the diagonal end is determined by what branch is run when abs(dx) == abs(dy) — here, it’s the vertical shift, and as such the diagonal always ends with a vertical shift. This causes a “wiggling” motion when dragging diagonally, as the entire diagonal segment shifts back and forth to compensate. Not ideal.

The key is that as we extend either the vertical or horizontal delta for the entire path, we want the diagonal end to switch rotations. This leads to the following:

void Tool::updatePath()
{
    // Clear output vector.
    m_tiles.clear();

    sf::Vector2i curr = m_dragStart;

    // Manhattan distance from m_dragStart to m_dragCurrent.
    const int dist = abs(m_dragStart.y - m_dragCurrent.y) +
                     abs(m_dragStart.x - m_dragCurrent.x);
    const bool odd = dist % 2 != 0;

    while (curr != m_dragCurrent) {
        m_tiles.push_back(curr);

        // Signed deltas
        const int dx = curr.x - m_dragCurr.x;
        const int dy = curr.y - m_dragCurr.y;

        if (abs(dx) > abs(dy)) {
            curr.x -= sign(dx);
        }
        else if (abs(dx) < abs(dy)) {
            curr.y -= sign(dy);
        }
        else {
            if (odd) {
                curr.x -= sign(dx);
            }
            else {
                curr.y -= sign(dy);
            }
        }
    }

    m_tiles.push_back(curr);
}

In this modified version, we take the Manhattan distance between start and current tiles. Then, if this number is odd, we shift horizontally when the deltas are equivalent, and if it’s even we shift vertically. Which rotation is used for odd/even is arbitrary, it only matters that they are different. Now, as we drag along the diagonal, the rotation of the end tile changes as the mouse crosses the tile boundaries, preserving our previous path and eliminating the “wiggle”.